Best answer:
Einstein's equation....
Einstein's equation applies to mass and energy, but not in the way that is frequently taught in beginning courses. The equation E=mc² is fraught with misconceptions, most of which come from well-meaning teachers and some who write about science. The equation is NOT about matter...
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Best answer: Einstein's equation....
Einstein's equation applies to mass and energy, but not in the way that is frequently taught in beginning courses. The equation E=mc² is fraught with misconceptions, most of which come from well-meaning teachers and some who write about science. The equation is NOT about matter being converted into energy or vice versa. But it's so easy to make that mistake because matter (which has mass) and energy seem so different and are measured in different units.... up to a point. (Physicists often measure both mass and energy in electron volts (as in MeV).
The problem is that the equation is portrayed as dealing with the CONVERSION of mass into energy, but that is not what it's all about. Instead, it deals with the CONSERVATION of mass and energy. The first problem deals with mass and energy as being two different things, when, instead, they are really the same thing. For lack of a better term it's called mass-energy.
Whether a nuclear reaction (where the mass-energy changes are more easily detected) or a chemical reaction reaction (where mass-energy changes are negligible and below the limit of detection), both energy and mass are conserved. One does not magically turn into the other.
Reactant1 + Reactant2 --> Product + energy
m-e(1) .......... m-e(2) ......... m-e(p) ... m-e(e)
m-e(1) + m-e(2) = m-e(p) + m-e(e) ........ conservation of mass-energy
Your question is flawed from the get-go. It asks, "How much of this mass was lost in the process?" And the answer is that no mass was lost in the reaction. Mass wasn't
"lost", nor was mass "converted" to energy. After the reaction there was just as much mass-energy as there was before the reaction. Too much is being read into the equation E=mc², things that it doesn't address.
If you want to gain a better understanding then you may want to do some additional reading:
https://plato.stanford.edu/entries/equivME/#2.1
or
https://scilearn.sydney.edu.au/fychemistry/tutorial_assignments/chem1901/week%202.pdf
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3 weeks ago