# Answer check on Calculus Question?

The driver of a car traveling at 50 ft/sec suddenly applies the brakes. The position of the car is s(t) = 50t - 2t^2, t seconds after the driver applies the brakes. How many seconds after the driver applies the brakes does the car come to a stop?
I know the equation for velocity would be v(t)=50-4t.
Since it says...
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The driver of a car traveling at 50 ft/sec suddenly applies the brakes. The position of the car is s(t) = 50t - 2t^2, t seconds after the driver applies the brakes. How many seconds after the driver applies the brakes does the car come to a stop?

I know the equation for velocity would be v(t)=50-4t.

Since it says earlier that the car is traveling at a velocity of 50 ft/sec, do I set the velocity equation to 50? Or do I just set it to 0 and solve for t which I got as 12.5 seconds?

I know the equation for velocity would be v(t)=50-4t.

Since it says earlier that the car is traveling at a velocity of 50 ft/sec, do I set the velocity equation to 50? Or do I just set it to 0 and solve for t which I got as 12.5 seconds?

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