Hi asked in Science & MathematicsMathematics · 8 months ago

How do you solve for x in: ln(3)=ln(10)-(0.1)(x)?

4 Answers

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  • 8 months ago
    Favourite answer

    Solve just like any equation:

    ln(3) = ln(10) - (0.1)(x)

    -0.1x = [ln(3) - ln(10)]

    x = [ln(3) - ln(10)] / -0.1 = 12.03972804

  • Philip
    Lv 6
    8 months ago

    ln(3) = ln(10) - (0.1)x, ie. ln(10) - ln(3) = ln(10/3) = (0.1)x. Multiply through

    bt 10 getting x = 10ln(10/3) = 10(1.203972804) = 12.0397804.

  • Vaman
    Lv 7
    8 months ago

    ln(3)=ln(10)-(0.1)(x)?

    0.1x = ln 10 -ln 3=ln 10/3

    10/3= e^(0.1x) =e^(x/10)

    x = 10 ln(10/3)=12.04

  • ?
    Lv 7
    8 months ago

    ln(3) =  ln(10) - (0.1)(x) ⇒

    0.1x = ln 10 - ln 3

    .......ln 10 - ln 3

    x = ---------------

    ............0.1

    ......2.30259 - 1.09861

    x = ------------------------

    ............0.1

    x = 12.0398......................ANS

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