# How do you solve for x in: ln(3)=ln(10)-(0.1)(x)?

### 4 Answers

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- stanschimLv 73 weeks agoFavorite Answer
Solve just like any equation:

ln(3) = ln(10) - (0.1)(x)

-0.1x = [ln(3) - ln(10)]

x = [ln(3) - ln(10)] / -0.1 = 12.03972804

- PhilipLv 63 weeks ago
ln(3) = ln(10) - (0.1)x, ie. ln(10) - ln(3) = ln(10/3) = (0.1)x. Multiply through

bt 10 getting x = 10ln(10/3) = 10(1.203972804) = 12.0397804.

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- VamanLv 73 weeks ago
ln(3)=ln(10)-(0.1)(x)?

0.1x = ln 10 -ln 3=ln 10/3

10/3= e^(0.1x) =e^(x/10)

x = 10 ln(10/3)=12.04

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- ?Lv 73 weeks ago
ln(3) = ln(10) - (0.1)(x) ⇒

0.1x = ln 10 - ln 3

.......ln 10 - ln 3

x = ---------------

............0.1

......2.30259 - 1.09861

x = ------------------------

............0.1

x = 12.0398......................ANS

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I simply subtracted ln(10) from each side and wrote the equation with the terms reversed from the original problem. Remember, try to isolate the unknown, x, on the left side of the equation when doing algebra.