How much was invested at each rate?
Struggling with these :( please help.
- Anonymous2 months agoFavourite answer
Let X be the amount invested at 6%. the amount invested at 9% is $3600 - X
X * 0.06 + ($3600 - X) * 0.09 = $270. X = $1800. Y = $1800
You should be able to do the rest now.
- KrishnamurthyLv 72 months ago
A financial services company invested
a person's IRA contribution of $3600 for one year at simple interest, yielding $270. Part of the money is invested at 6% and the rest at 9%. How much was invested at each rate? Complete the following table, letting x = the number of dollars invested at 6% and y = the number of dollars invested at 9%.