# How much was invested at each rate?

Struggling with these :( please help.

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- Anonymous2 months agoFavourite answer
Let X be the amount invested at 6%. the amount invested at 9% is $3600 - X

X * 0.06 + ($3600 - X) * 0.09 = $270. X = $1800. Y = $1800

You should be able to do the rest now.

- KrishnamurthyLv 72 months ago
A financial services company invested

a person's IRA contribution of $3600 for one year at simple interest, yielding $270. Part of the money is invested at 6% and the rest at 9%. How much was invested at each rate? Complete the following table, letting x = the number of dollars invested at 6% and y = the number of dollars invested at 9%.

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