how would i factor out the "k" in this equation?

Question

y= -2f(2x + 6) + 6

Answer 1

You need your eyes tested!

Answer 2

Since there is no k in the equation, the only way to factor it out would be to add an 1/k as neutralizing element. I don't know why you'd want to do that but you could:

.

y = -2f (2x + 6) + 6

--> y = k (1/k (-2f (2x + 6) + 6))

or  y = k (-2f/k (2x + 6) + 6/k)

Answer 3

Where is the 'k'?

Answer 4

I’ll take a guess you meant the “f”?

y = -2f(2x + 6) + 6

y - 6 = -2f(2x + 6) + 6 - 6

y - 6 = -2f(2x + 6)

(y - 6)/ -2 = [-2f(2x + 6)]/-2

-½y + 3 = f(2x + 6)

(-½y + 3)/(2x +6) = f(2x +6)/(2x + 6)

(-½y + 3)/(2x +6) = f

Answer 5

There is no k in the equation.

Answer 6

Your equation has no k.  Can you provide more context?  What does k in quotes really mean?

Answer 7

Hint: rewrite as y - 6 = -2f(2(x+3)). 

Unanon yourself and I will detail more if need be. 

Answer 8

Since there is no “k” in that equation, I can’t factor it out.