Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

how would i factor out the "k" in this equation?

y= -2f(2x + 6) + 6

8 Answers

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  • Anonymous
    1 month ago

    You need your eyes tested!

  • Zac Z
    Lv 7
    1 month ago

    Since there is no k in the equation, the only way to factor it out would be to add an 1/k as neutralizing element. I don't know why you'd want to do that but you could:

    .

    y = -2f (2x + 6) + 6

    --> y = k (1/k (-2f (2x + 6) + 6))

    or  y = k (-2f/k (2x + 6) + 6/k)

  • 1 month ago

    Where is the 'k'?

  • 1 month ago

    I’ll take a guess you meant the “f”?

    y = -2f(2x + 6) + 6

    y - 6 = -2f(2x + 6) + 6 - 6

    y - 6 = -2f(2x + 6)

    (y - 6)/ -2 = [-2f(2x + 6)]/-2

    -½y + 3 = f(2x + 6)

    (-½y + 3)/(2x +6) = f(2x +6)/(2x + 6)

    (-½y + 3)/(2x +6) = f

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  • 1 month ago

    There is no k in the equation.

  • 1 month ago

    Your equation has no k.  Can you provide more context?  What does k in quotes really mean?

  • rotchm
    Lv 7
    1 month ago

    Hint: rewrite as y - 6 = -2f(2(x+3)). 

    Unanon yourself and I will detail more if need be. 

  • 1 month ago

    Since there is no “k” in that equation, I can’t factor it out.

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