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# what is the slope intercept form of m=2 with pints (5, -2)?

Update:

What is the standard form with the same given?

### 10 Answers

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• You are given the slope of the line m=2 & a

point (5,-2). So, it is sufficient to determine

the equation of the line by the point-slope

form:

y-(-2)=2(x-5)

=>

y+2=2x-10

=>

y=2x-12

The standard form is

2x-y-12=0

• line | through (5, -2)

slope 2 | slope-intercept equation

y = 2 x - 12

• The typical equation of a line is: y = mx + y₀ → where m: slope and where y₀: y-intercept

The slope of the line is: m = 2

The equation of the line becomes: y = 2x + y₀

The line passes through (5 ; - 2), so these coordinates verify the equation of the line.

y = 2x + y₀

y₀ = y - 2x → you substitute x and y by the coordinates of the point (5 ; - 2)

y₀ = - 2 - (2 * 5)

y₀ = - 12

The equation of the line is: y = 2x - 12

• slope intercept form: y = mx + c

so y = 2x + c

when x = 5 y = -2

so -2 = 10 + c

==> c = -12

hence y = 2x - 12

standard form: -2x + y = -12

or...

since for a line, the slope is constant:

slope = rise /run

so, from any point (x, y) to a given point like (5, -2)

(y + 2)/(x - 5) = 2

==> y + 2 = 2x - 10

==> y = 2x - 12

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• Well, calling your coordinates (x1, y1)

We can make use of the formula often written as follows:

y-y1 = m(x-x1)

Substitute in the givens:

y-(-2)=2(x-5)

y+2 = 2x-10  (Distributive property)

y =2x-12       (Subtract 2 from both sides.)

Slope =2, intercept = -12

• y - (-2) = 2(x - 5)

y + 2 = 2x - 10

y = 2x - 12

• y  - - 2 = 2(x - 5)

y + 2 = 2x - 10

y = 2x - 12

Slope ; m = 2

Intercept  ; c = -12

• y = mx + b

-2 = 2(5) + b

- 2 = 10 + b

b = - 2 - 10

b = - 12

The slope intercept for is y = 2x - 12

the standard form of the equation is 2x - y = 12...

• We have an equation of the form y = mx + c

so, -2 = 2(5) + c

Then, c = -12

Hence, y = 2x - 12....slope intercept form

and y - 2x + 12 = 0...standard form

:)>

• y+2= 2(x - 5)

y= 2x - 12

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